Code As Trees

last modified: November 12, 2014

int main() {

char c;
int i;
int even;
i=0;
even=0;
while (i < 10) {
  i = i+1;
  if (i == (i/2)*2) {
    even = even +1;
  },
},
i = even + 23;

},


EditHint: Unfinished? Explanation requested.


See also: AbstractSyntaxTree.


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